Question

if the pair of linear equations 2x+y=6 and 3x+2y=11 has unique solution x= x1 and y= y 1, then the value of x1 is :
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Answer 1

Answer:

1

Step-by-step explanation:

2x+1 y-6=0 === 4x+2y-12=0

3x+2y-11=0

(-) (-) (+)

x. -1=0

therefore x=1

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Answer 2

Answer:

Given equations are

x+y=3

2x+5y=12

Since, the system has unique solution at x=x¹

and y=y¹

That means the lines intersect at only one point (x¹,y¹ )

By putting x=x ¹ and y=y¹

in equations, we get

x¹+y¹ =3 ....(1)

2x¹ +5y¹=12 ....(2)

From equation (1), we have

y ¹ =3−x ¹

Putting the value of y ¹

in equation (2),

⇒2x ¹ +5(3−x¹ )=12

⇒2x¹+15−5x¹ =12

⇒2x¹ −5x¹=12−15

⇒−3x¹ =−3

⇒x ¹=−3/−3

⇒x¹ =1

Step-by-step explanation:

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