if the pair of lines b2x2-a2y2=0 are inclined at an angle theta then find the eccentricity of the standard hyperboa?
Answers
Answered by
0
Answer:
Consider b
2
x
2
−a
2
y
2
=0
⇒b
2
x
2
=a
2
y
2
⇒y
2
=
a
2
b
2
x
2
⇒y=±
a
b
x
Thus b
2
x
2
−a
2
y
2
=0 is a pair of intersecting lines y=
a
b
x and y=−
a
b
x
The angle between them is 2θ=2tan
−1
(
a
b
).
Also y=
a
b
x and y=−
a
b
x represents the asymptotes of the hyperbola with eccentricity e=secθ or e=
a
a
2
+b
2
Similar questions