Question

If the pd is 220v and current I is40 ampere then find resistance

Answer 1

Solution :

⏭ Given:

✏ Potential difference = 220V

✏ Current flow = 40A

⏭ To Find:

✏ Magnitude of resistance

⏭ Formula:

✏ As per ohm's law, Relation between potential difference and current flow is given by

$\star \: \boxed{ \rm{ \large\bold{ \pink{V = I \times R}}}} \: \star$

⏭ Terms indication:

✏ V denotes potential difference

✏ I denotes current

✏ R denotes resistance

⏭ Calculation:

$\mapsto \sf \: R = \dfrac{V}{I} \\ \\ \mapsto \sf \: R = \dfrac{220}{40} \\ \\ \mapsto \: \boxed{ \bold{ \sf \large{ \orange{R = 5.5 \: \Omega}}}} \: \gray{ \bigstar}$

Answer 2

$\huge{ \mathtt{ \fbox{Solution :) }}}$

Given ,

• Potential difference (v) = 220 v
• Current (I) = 40 amp

We know that , the ohm's law is given as

$\large \mathtt{ \fbox{V = IR}}$

Thus ,

220 = 40 × R

R = 220/40

R = 5.5 ohm

Hence , the resistance is 5.5 ohm

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