If the percentage error in measurement of radius of sphere is 0.2%. what would be error in volume of sphere
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real r = r1-0.2r1/100
r=9.8r1/100
substituting this in the formula you will get the error as0.125% in the volume of the sphere
r=9.8r1/100
substituting this in the formula you will get the error as0.125% in the volume of the sphere
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