Question

If the percentage error in the measurement of V and I are 2% and 3% find the percentage error in the measurement of resistance in an experiment bracket Ohm's law bracket close

Answer 1

given∆V/V*100=2%

∆I/I*100=3%

R=V/I

therefore ∆R/R=∆V/V+∆I/I

∆R/R*100=∆V/V*100+∆I/I*100

∆R/R*100=2+3=5%

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