if the percentage increse in the area of circle is 44% what will be the percentage increase in its circumference?
Answers
Answered by
0
Answer:
Area of smaller circle = pix r^2
Area of larger circle = 1.44 pi x r^2 = pi x(1.2r)^2
So the radius should be increased by 20 percent to have a circle with an area increased by 44 percent.
Answered by
66
❐ FULL EXPL@NATION:
.
Let The radius(r) of Circle be x.
As We Know That,
Area of Circle = π × r²
So,
- The Area of Circle = πx²
Circumference of Circle = 2πr
So,
- The Circumference of Circle = 2πx
After Increasing,
- ❥ Area of Circle = πx² + πx² × 44/100
- ❥ Area of Circle = πx² [1 + 11/25]
- ❥ Area of Circle = πx² [36/25]
- ❥ Area of Circle = π {x[6/5]}²
- ❥ π × R² = π (6x/5)²
[Comparing both sides]
- ❥ R = 6x/5
So,
- The New radius is 6x/5.
As We Know That,
- ❥ Circumference of New Circle = 2πR
- ❥ Circumference of New Circle = 2π × 6x/5
- ❥ Circumference of New Circle = 12πx/5
So,
- The Circumference of New Circle is 12πx/5.
As We Know That,
- ❥ Increase Percentage = Difference/Old Value × 100
- ❥ Increase Percentage = (12πx/5 - 2πx)/2πx × 100
- ❥ Increase Percentage = [(12πx - 10πx)/2πx] / 2πx × 100
- ❥ Increase Percentage = 2πx/5 × 1/2πx × 100
- ❥ Increase Percentage = 1/5 × 100
- ❥ Increase Percentage = 20%
So,
- The Increase Percentage in Circumference of Circles is 20%.
❐ REQUIRED ANSWER:
- The Increase Percentage in Circumference of Circles is 20%.
Similar questions