Math, asked by 7esuryanshumohansing, 9 hours ago

if the percentage increse in the area of circle is 44% what will be the percentage increase in its circumference?​

Answers

Answered by ajayjha29
0

Answer:

Area of smaller circle = pix r^2

Area of larger circle = 1.44 pi x r^2 = pi x(1.2r)^2

So the radius should be increased by 20 percent to have a circle with an area increased by 44 percent.

Answered by Anonymous
66

FULL EXPL@NATION:

.

Let The radius(r) of Circle be x.

As We Know That,

Area of Circle = π × r²

So,

  • The Area of Circle = πx²

Circumference of Circle = 2πr

So,

  • The Circumference of Circle = 2πx

After Increasing,

  • ❥ Area of Circle = πx² + πx² × 44/100
  • ❥ Area of Circle = πx² [1 + 11/25]
  • ❥ Area of Circle = πx² [36/25]
  • ❥ Area of Circle = π {x[6/5]}²
  • ❥ π × R² = π (6x/5)²

[Comparing both sides]

  • R = 6x/5

So,

  • The New radius is 6x/5.

As We Know That,

  • ❥ Circumference of New Circle = 2πR
  • ❥ Circumference of New Circle = 2π × 6x/5
  • ❥ Circumference of New Circle = 12πx/5

So,

  • The Circumference of New Circle is 12πx/5.

As We Know That,

  • ❥ Increase Percentage = Difference/Old Value × 100
  • ❥ Increase Percentage = (12πx/5 - 2πx)/2πx × 100
  • ❥ Increase Percentage = [(12πx - 10πx)/2πx] / 2πx × 100
  • ❥ Increase Percentage = 2πx/5 × 1/2πx × 100
  • ❥ Increase Percentage = 1/5 × 100
  • Increase Percentage = 20%

So,

  • The Increase Percentage in Circumference of Circles is 20%.

REQUIRED ANSWER:

  • The Increase Percentage in Circumference of Circles is 20%.

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