Question

if the peremeter of a square is 120cm find its area and length of diagonal​

Answer 1

Step-by-step explanation:

Area of rhombus =1/2 D1*D2 =1/2 *10 *d2 =120

D2 =120/4 =24

Half of D1=10/2 =5

Half of D2=24/2 =12

Side = sq root of [5^2+12^2]= sq root of[25+144]

sq root of[169] =13

perimeter =13*4 =52cms

Answer : perimeter is =52cms

Answer 2

$\bold{\tt{\red{\bigstar \: Solution : }}}$

$\:$

$\tt{\green{perimeter \: of \: square = 120cm}}$

$\tt{\green{\implies 4 \times side = 120cm}}$

$\tt{\green{\implies side = \frac{120cm}{4}}}$

$\tt{\green{\implies side = 30cm}}$

$\:$

$\tt{\orange{area \: of \: square = {(side)}^2}}$

$\tt{\orange{\implies area \: of \: square = {(30cm)}^2}}$

$\tt{\orange{\implies area \: of \: square = {900cm}^2}}$

$\:$

$\tt{diagonal \: of \: square = \sqrt{2 \times {(side)}^2}}$

$\tt{\implies diagonal \: of \: square = \sqrt{2 \times {(30cm)}^2}}$

$\tt{\implies diagonal \: of \: square = \sqrt{{900cm}^2}}$

$\tt{\implies diagonal \: of \: square = \sqrt{ {1800cm}^2}}$

$\tt{\implies diagonal \: of \: square = 42.42cm}$