Math, asked by hdeka1112, 1 year ago

If the perimeter of a rectangle is 138 metres and the difference between the length

and the breadth is 7 metres, what is the area of the rectangle?​

Answers

Answered by khagenkdey
1

Answer:

length =38m

breadth =31m

Step-by-step explanation:

Let,

length =x

breadth=x-7

2(x+x-7)=138

4x-14=138

4x= 138+14

x=152/4

=38

length =38m

breadth=(38-7)

=31m

Answered by yashugarg002
0

Answer:

Perimeter of rectangle = 138 m

Length of rectangle = x m

Breadth of rectangle = (x - 7) m

Perimeter = 2 ( l + b )

138 = 2 ( x + (x - 7) )

138 = 2 ( 2x - 7)

138 = 4x - 14

4x - 152 = 0

4x = 152

x = 152÷4

x = 38

So, Length of rectangle = 38 m

Breadth of rectangle = 38 -7

= 31 m

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