Question

if the perimeter of a rectangle is 68 m in the length is 14 m more than the width what are the dimension of the rectangle

Answer 1

Let width=x m
and length=x+14m
Perimeter=68m
2(l+b)=68
2(x+x+14)=68
x+14+x=34
2x=20
x=10m
So, length=x+14=10+14=24m
and breadth=x=10m.

Answer 2

The dimensions of the rectangle are 24 m and 10 m.

Given: Perimeter = 68 m; length is 14 m more than the width

To Find: Dimensions of the rectangle

Solution: Let, the length of the rectangle = a meters

Let, the width of the rectangle = b meters

From the information given in the question:

a = b + 14 (Equation 1)

The perimeter of a rectangle = 2(a + b)

Putting the value of a from equation 1:

2 (b + 14 + b)

2 (2b + 14)

Opening the brackets:

The perimeter of the rectangle = 4b + 28

Since the perimeter of the rectangle is 68 m.

So, 4b + 28 = 68

4b = 68 - 28

4b = 40

b = 40/4

b = 10 m

Now, putting the resultant value of b in equation 1:

a = b + 14

a = 10 + 14

a = 24 m

Therefore, the length of the rectangle is 24 m and the width of the rectangle is 10 m.

#SPJ2