Question

. If the perimeter of a rhombus is 100 cm and one of the diagonals is 40 cm, then the area of the rhombus is in square centimetres is​

Answer 1

=> We know that the all sides of a rhombus is equal.

=> And given the perimeter of rhombus is 100 cm.

=> Then sides of rhombus = 100/4 = 25 cm and given one diagonals = 40 cm

=> We know that the diagonals of rhombus bisects at triangle and intersect equal parts.

=> Let others diagonals is 2x

=> ( x )² + ( 20 )² = ( 25 )²

=> x² = 625 - 400 = 225

=> So x = 15 and other diagonals = 2 × 15 = 30 cm

=> Then area of rhombus = Diagonals × Diagonal / 2

=> 40 × 30 / 2

=> 600 cm²

I hope this will help you dear..

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