if the perimeter of a semicircular park is 72 m,find it area and radius
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Answered by
3
Perimeter of semi circle = pi *r + 2r
=> pi *r + 2r = 72
=> 22r/7 + 2r = 72
=> (22r+14r) / 7 = 72
=> 36r/7 = 72
=> r = 72 * 7 / 36
=> r = 2 * 7
=> r = 14 m
Area = pi *r^2 / 2
= 22 * 14 * 14 / 7*2
= 22 * 14 * 2/2
= 44 * 14 / 2
= 616 /2
= 308 m^2
=> pi *r + 2r = 72
=> 22r/7 + 2r = 72
=> (22r+14r) / 7 = 72
=> 36r/7 = 72
=> r = 72 * 7 / 36
=> r = 2 * 7
=> r = 14 m
Area = pi *r^2 / 2
= 22 * 14 * 14 / 7*2
= 22 * 14 * 2/2
= 44 * 14 / 2
= 616 /2
= 308 m^2
Answered by
3
Perimeter or circumference of a circle =( 2×72)m = 144m
circumference = 144m
2 pie R = 144m
2 R = 144 ÷ 22/7
R = 144 ÷ 22/7 ÷2
= 252/11
Area = Pie R^2
= 22/7 × (252/11 )^2
= 18144/11 m^2
circumference = 144m
2 pie R = 144m
2 R = 144 ÷ 22/7
R = 144 ÷ 22/7 ÷2
= 252/11
Area = Pie R^2
= 22/7 × (252/11 )^2
= 18144/11 m^2
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