The vertical angle of an isosceles triangle is 100 . find its base angles.
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Answered by
6
So....
vertical angle =100°
by angle sum property
100+x+x=180° (2 angles of an isoceles triangle are equal)
2x=(180-100)°
x=40°
HOPE IT HELPS
vertical angle =100°
by angle sum property
100+x+x=180° (2 angles of an isoceles triangle are equal)
2x=(180-100)°
x=40°
HOPE IT HELPS
Answered by
2
hiii!!!
here's ur answer...
the vertical angle of the isosceles triangle is 100°.
we know that there are two sides which have equal length and angle in an isosceles triangle.
if the vertical angle is 100° then the both base angles will have equal angles.
by angle sum property:-
let the three angles be a, b and c.
b = c
=> a+b+c = 180°
=> 100+2b = 180°
=> 2b = 180-100
=> 2b = 80°
=> b = 80/2
=> b = 40°
hence the base angles of the isosceles triangle are 40° each.
hope this helps u...!
here's ur answer...
the vertical angle of the isosceles triangle is 100°.
we know that there are two sides which have equal length and angle in an isosceles triangle.
if the vertical angle is 100° then the both base angles will have equal angles.
by angle sum property:-
let the three angles be a, b and c.
b = c
=> a+b+c = 180°
=> 100+2b = 180°
=> 2b = 180-100
=> 2b = 80°
=> b = 80/2
=> b = 40°
hence the base angles of the isosceles triangle are 40° each.
hope this helps u...!
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