Question

If the perimeter of a square is 40 cm, find (i) the length of a diagonal, and (ii) its area.​

Answer 1

Answer:

Step-by-step explanation:

=40 cm Side = 10 cm     As S=P/4 (in square) Area = side×side             =10×10               =100cm^2 Diagonal => 10^2 +10^2=diagonal^2 (Pythagoras theorem) Diagonal =root (100 +100) Diagonal = root 200    Ans

Answer 2

Step-by-step explanation:

Perimeter of the square=40 cm

Let the side be a

The perimeter of the square=40 cm

4a=40

a=10

Therefore the side of the square is 10 cm

Diagonal of the square

\begin{gathered}=\sqrt{2 a^{2} } \\ =\sqrt{2 (10^{2}) } \\ =\sqrt{200} \\ =14.14 cm\end{gathered}=2a2=2(102)=200=14.14cm

Area of the square = a^{2}a2

                                =100sq.cm

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