Question

if the perimeter of a Trapezium B 52 CM its non parallel sides are equal to 10 cm each and its altitude is 8 cm find the area of the trapezium

Answer 1

$\textbf{\huge{ANSWER:}}$

Given:

Perimeter of Trapezium = 52 cm

Non parallel sides = 10 each

As there are 2 non parallel sides, the sum will be equal to 10 + 10. Doing the same, we get:

Sum of non parallel sides = 20 cm ( 10 + 10 )

Altitude = 8 cm

Sum of parallel sides = 52 - 20

=》 $\textbf{32 cm}$

Area of a trapezium:

$\frac{1}{2} \times Sum\:of\:parallel\:sides \times Altitude$

Putting all the values in the formula:

=》 $\frac{1}{2} \times 32 \times 8$

=》 32 × 4 ${cm}^{2}$

=》 $128 {cm}^{2}$

Hope it Helps!! :)

Answer 2

The perimeter of a trapezium is 540 cm, If the non parallel sides are 10 cm each and the altitude is 8 cm, what is the area of the trapezium?

=The area of a trapezium = sum of the parallel sides * altitude/2. Here

it is (540–10–10)*8/2

= 520*8/2

=2080 sq cm.