what is the zero of the following : (1) 1+3x-18x^2
(2)8x^2-14x-15
(3)x^2-4x
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Hello Friend!!!
⭐ Here's your answer,
1) 1 + 3x -18x²
==> 1 + 6x - 3x -18x²
==> 1(1 + 6x) -3x ( 1 + 6x)
==> (1 + 6x)(1 - 3x)
==> x = -1 / 6 or x = 1 / 3
2) 8x² -14x -15 = 0
==> It's a wrong question
==> 2) 8x² -14x + 5 =0 is the right question
==> 8x² - 14x + 5 =0
==> 8x² - 10x -4x + 5 =0
==> 2x(4x - 5) -1 (4x -5)= 0
==> (2x -1 )(4x -5) =0
==> x = 1 / 2 or x = 5 / 4
3) x² - 4x = 0
==> x( x - 4 ) = 0
==> x = 0 or x = 4
⏮ HOPE IT HELPS YOU : ) ⏭
⭐ Here's your answer,
1) 1 + 3x -18x²
==> 1 + 6x - 3x -18x²
==> 1(1 + 6x) -3x ( 1 + 6x)
==> (1 + 6x)(1 - 3x)
==> x = -1 / 6 or x = 1 / 3
2) 8x² -14x -15 = 0
==> It's a wrong question
==> 2) 8x² -14x + 5 =0 is the right question
==> 8x² - 14x + 5 =0
==> 8x² - 10x -4x + 5 =0
==> 2x(4x - 5) -1 (4x -5)= 0
==> (2x -1 )(4x -5) =0
==> x = 1 / 2 or x = 5 / 4
3) x² - 4x = 0
==> x( x - 4 ) = 0
==> x = 0 or x = 4
⏮ HOPE IT HELPS YOU : ) ⏭
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