Question

If the perimeter of a triangle is (4y-3x+2z) cm and two sides of the triangle measure (4x+2y+z)cm and (3x+7y-2z)cm, find the length of the third side of the triangle.

Answer 1

perimeter of a triangle = sum of all sides of triangle
given sides= (4x+2y+z) , (3x+7y-2z)
then perimeter = 4x+2y+z+3x+7y-2z+third side= -3x+4y+2z
7x+9y-z+ third side=-3x+7y-2z
third side = -10x -2y -z

Answer 2

given perimeter = 4y-3x+2z
also 2 sides are 4x+2y+z and 3x+7y-2z
let other side be a
so p = a + other 2 sides
a = p - other sides
a = 4y-3x+2z -(4x+2y+z+3x+7y-2z)
a= 4y -3x+2z-4x-2y-z-3x-7y+2z
a= -5y-10x+3z