Question

prove the following as irrational numbr √3/5​

Answer 1

Answer:

Step-by-step explanation:

Hi friend!!

Let √3/5 be a rational number.

A rational number can be written in the form of p/q where p,q are integers.

√3/5 = p/q

√3 = p/q-√5

Squaring on both sides,

(√3)² = (p/q-√5)²

3 = p²/q²+√5²-2(p/q)(√5)

√5×2p/q = p²/q²+5-3

√5 = (p²+2q²)/q² × q/2p

√5 = (p²+2q²)/2pq

p,q are integers then (p²+2q²)/2pq is a rational number.

Then √5 is also a rational number.

But this contradicts the fact that √5 is an irrational number.

So,our supposition is false.

Therefore, √3/5 is an irrational number.

Answer 2

Step-by-step explanation:

√3/5=a/b let it is rational no. and equal to a/b bnoy equal to 0

√3=5a/b

√3 is irrational while 5a/b is rational no. they can't be equal .so our supposition is wrong