if the perimeter of semicircular protector is 108 then find the diameter of the protector
Answers
Answered by
4
Perimeter=108cm
Pi x r +2r=108
r(22/7+2)=108
r(22+14/7)=108
r(36/7)=108
r=108x7/36
r=3x7
r=21cm
Therefore, d=2r
=2x21=42cm
Pi x r +2r=108
r(22/7+2)=108
r(22+14/7)=108
r(36/7)=108
r=108x7/36
r=3x7
r=21cm
Therefore, d=2r
=2x21=42cm
Sarth45:
why
Answered by
4
perimeter of semicircle=pie×r+d
108=22/7×d/2+d
108=11d/7+d
108=11d+7d/7
108=18d/7
d=108×7/18
d=42 units
[Note-remember when you are going to ask questions related to maths don't forget to write units]
108=22/7×d/2+d
108=11d/7+d
108=11d+7d/7
108=18d/7
d=108×7/18
d=42 units
[Note-remember when you are going to ask questions related to maths don't forget to write units]
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