if the perimeter of semicircular protector is 108 then find the diameter of the protector
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Answered by
4
Perimeter=108cm
Pi x r +2r=108
r(22/7+2)=108
r(22+14/7)=108
r(36/7)=108
r=108x7/36
r=3x7
r=21cm
Therefore, d=2r
=2x21=42cm
Pi x r +2r=108
r(22/7+2)=108
r(22+14/7)=108
r(36/7)=108
r=108x7/36
r=3x7
r=21cm
Therefore, d=2r
=2x21=42cm
Sarth45:
why
Ok let it be in meter its my mistake I have written cm sorry for that
yarrr write only units
not meter or centimetre
Ok and thanks for reporting it
my pleasure
Ya its ur pleasure only
hmm
Bydave in which class u r
don't talk here come in inbox
Answered by
4
perimeter of semicircle=pie×r+d
108=22/7×d/2+d
108=11d/7+d
108=11d+7d/7
108=18d/7
d=108×7/18
d=42 units
[Note-remember when you are going to ask questions related to maths don't forget to write units]
108=22/7×d/2+d
108=11d/7+d
108=11d+7d/7
108=18d/7
d=108×7/18
d=42 units
[Note-remember when you are going to ask questions related to maths don't forget to write units]
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