If the perimeter of the room is 40m and height is4m then area of its four walls is.
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area of room =perimeter÷4
=40÷4
=10m
hight =4m
width =10m
length =10m
area= h×l×w
= (4×10×10)
= 400 m square
I hope it helps you
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=40÷4
=10m
hight =4m
width =10m
length =10m
area= h×l×w
= (4×10×10)
= 400 m square
I hope it helps you
please mark brainliest
Answered by
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Given:- Perimeter of the rectangular floor:-40m
Height of the room:-4m
To find:- Area of the four walls or CSA of the room.
Solution:- We know that the CSA of a cuboid:- 2h(l+b)
or:- hx2(l+b)
Also, 2(l+b)= Perimeter of the rectangle. So,
CSA of Room:- hx40
:- 4x40
:- 160m^2
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