Math, asked by prathamkumbhare871, 1 year ago

If the perimeter of the room is 40m and height is4m then area of its four walls is.

Answers

Answered by ashmit2466
0
area of room =perimeter÷4
=40÷4
=10m
hight =4m
width =10m
length =10m

area= h×l×w
= (4×10×10)
= 400 m square


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Answered by Anonymous
0

Given:- Perimeter of the rectangular floor:-40m

Height of the room:-4m

To find:- Area of the four walls or CSA of the room.

Solution:- We know that the CSA of a cuboid:- 2h(l+b)

or:- hx2(l+b)

Also, 2(l+b)= Perimeter of the rectangle. So,

CSA of Room:- hx40

:- 4x40

:- 160m^2

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