Question

If the perimeters of a rectangle and a square are equal and the ratio of the two adjacent sides of the rectangle is 1:2 then the ratio of area of the rectangle and that of the square is
Answer is 8:9 please explain it​

Answer 1

Answer:

Step-by-step explanation:

Let sides of the rect. be a, 2a

perimeter of rect = 2( a + 2a ) = 6a = perimeter of square

Let sides of square be s

perimeter of square = 4s

=> 4s = 6a

=> s = 3/2a

    Area of square = (3/2a)(3/2a) = 9/4$A^{2}$

   Area of rect. = a*2a = 2$A^{2}$

Ratio of ar. Of square to that of rect -

9/4 : 2 = 9:2*4

= 9 : 8

Answer 2

Step-by-step explanation:

This is your answer mate.