If the perimeters of circle A and circle B are 88 m and 154 m respectively, what is the sum of their diameters? (In m)
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Answer:
Step-by-step explanation:
Perimeter of circle A = 88 m =2*22/7*R
2*22/7*R =88
R=14m
Hence the diameter is 28 m
Perimeter of circle B=154 m=2*22/7*R2
2*22/7*R2 =154 m
R2=49/2m
Hence the diameter is 49 m
D1+ D2 = 28+49=77 m
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