Question

If the perimeters of two squares are in the ratio a:b, prove that their areas are in the ratio a2:b2.

Answer 1

Since, the ratio of perimeter of 2 squares is a:b

Then, side of 1st square = a/4

Therefore, area of 1st sq. = a/4×a/4

= a^2/16

Similarly, side of 2nd square = b/4 Therefore, area of 2nd sq. = b/4×b/4

= b^2/16

Now,

Ratio of area of these 2 squares

= a^2/16 : b^2/16

= a^2 : b^2

HOPE IT HELPS :-D

Answer 2

Step-by-step explanation:

above answer is correct