Question

if the persentage error in the measurement of volume of a sperical balloon is 3%then the percentage error in the measurement of its radius is​

Answer 1

Answer:

0.09

Explanation:

Volume of sphere is given by

V=43πR3

Where R is radius of sphere

ΔVV=3ΔRR

Hence, percentage error in volume

ΔVV×100=3(ΔRR)×100%

=3×3%=9%

9×1/100=0.09