Question

If the Planck’s constant, h=6.6×10-34 J-s, the de Broglie wavelength in of a particle having momentum 3.3×10-24 kg ms-1 will be

Answer 1

Answer:

hope the answer will help you

Answer 2

$in \: this \: question \: simply \: use \: the \: formula \\ of \: debrogile \: wavelength \\ according \: to \: his \: concept \\ wavelength = \frac{h}{mv} \: \: where \: h \: is \: plank \: constant \\ putting \: the \: value \: we \: get \\ wavelength = \frac{6.626 \times {10}^{ - 34} }{3.3 \times {10}^{ - 4} } = 2 \times {10}^{ - 30} \\ hence \: required \: wavelengt \: is \: 2 \times {10}^{ - 30} \\ {hope \: it \: helps \: u}$