Question

If the point (2,-2) lies on the graph of the linear equation 5x+ky=4, find the value of k.

Answer 1

Answer:

point 2,-2 satisfies the equation

5x +ky=4

5×2+k×-2=4

-2k=-6

k=3

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Answer 2

Concept :  

An equation which can be put in the form ax + by + c = 0, where a, b & c are real numbers x, y are variables, is called linear equation in two variables.

In equation ax + by + c = 0, the values of x and y are always real.

ax + by + c = 0 is also called standard form a linear equation in two variables.

 

Given :  The point (2, -2) lies on the graph of the linear equation 5x + ky = 4.

 

On putting x = 2 and y = - 2 in the given linear equation 5x + ky = 4.

⇒ 5 × 2 - 2k = 4

⇒ 10 - 2k = 4

⇒ - 2k = 4 - 10

⇒ - 2k = - 6

⇒ 2k = 6

⇒ k = 6/2

⇒ k = 3

Hence, the value of k is 3.

HOPE THIS ANSWER WILL HELP YOU…..

 

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