Question

If the point (-2,4) lies on the graph of the equation (a-1)y+3x=6 find two more solution of this equation? (with calculation)​

Answer 1

Answer:

Step-by-step explanation:

point(-2,4) lies on

(a-1)y+3x=6

so (a-1)(4)+3(-2)=6

4a-4-6=6

4a=16

a=4

So the equation is:

3x+3y=6

or x+y=2

putting x=1,2

y=1,0

so other solutions are

(1,1),(2,0)

Answer 2

The two solutions of given equation = (0,2) and (2,0)

Explanation:

Given linear equation : $(a-1)y+3x=6$ (1)

If (-2,4) lies on the graph of the equation  $(a-1)y+3x=6$ , then

(-2,4) should satisfy this equation.

At (x,y) =(2,3)

$(a-1)(4)+3(-2)=6$

$(a-1)(4)-6=6$

$(a-1)(4)=12$

$(a-1)=\dfrac{12}{4}=3$

$a=3+1=4$

Put value of in (1) , we get

$(4-1)y+3x=6$

$3y+3x=6$

$y+x=2$  [Divide both sides by 3]

Put x= 0 , y=2

Put y= 0 , x= 2

So , the two solutions of given equation = (0,2) and (2,0)

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