Question

If the point ( + 3, 3 − 2) is a solution of linear equation 2 + 5y + 12 = 0, find the value of �

Answer 1

Answer:

1

Step-by-step explanation:

Correct option is

A

1

Given equations are

x+y=3

2x+5y=12

Since, the system has unique solution at x=x

1

and y=y

1

That means the lines intersect at only one point (x

1

,y

1

)

By putting x=x

1

and y=y

1

in equations, we get

x

1

+y

1

=3 ....(1)

2x

1

+5y

1

=12 ....(2)

From equation (1), we have

y

1

=3−x

1

Putting the value of y

1

in equation (2),

⇒2x

1

+5(3−x

1

)=12

⇒2x

1

+15−5x

1

=12

⇒2x

1

−5x

1

=12−15

⇒−3x

1

=−3

⇒x

1

=

−3

−3

⇒x

1

=1

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Answer 2

Answer:

Time Remaining:01:22:57

Question : Il Section - B. Reasoning Arempt all questions (Write statements, wore out the

question in notebook click picture and upload it in Educore)

State whether True or False. Justify your answer with example. a) When we add two consecutive triangular numbers, we will get square

numbers. b) Squares of all odd numbers are odd.

Enter Answer