if the point (3,4) lies on graph of equation 3y+ax+7 find the value of a come on i gave more points coz its urgent
Answers
Answered by
1
(3,4) lies on the graph
⇒x=3 and y=4 is the solution of the equation
3y+ax+7=0
3(4)+a(3)+7=0
12+3a+7=0
19+3a=0
⇒a=-19/3
⇒x=3 and y=4 is the solution of the equation
3y+ax+7=0
3(4)+a(3)+7=0
12+3a+7=0
19+3a=0
⇒a=-19/3
sharmilafareedp30hcc:
please mark my answer as brainliest if it helped you.
Answered by
9
hay!!
we know in (3,4) 3=x, 4=y
Then put the value in given equation
3y + ax + 7
=> 3(4) + a(3) + 7 =0
=> 3×4 + a×3 + 7 =0
=> 12 + 3a + 7 =0
=> 19 + 3a =0
=> 3a = -19
=> a = -19/3
I hope it's help you
we know in (3,4) 3=x, 4=y
Then put the value in given equation
3y + ax + 7
=> 3(4) + a(3) + 7 =0
=> 3×4 + a×3 + 7 =0
=> 12 + 3a + 7 =0
=> 19 + 3a =0
=> 3a = -19
=> a = -19/3
I hope it's help you
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