if the point (3, 5) lies on the graph of the equation ax+y=20
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a×3+5=20
3a+5=20
3a=20-5
3a=15
a=15/3
a=5
Anonymous:
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If the point (3,5) lies on the graph ax+y = 20
Then, x = 3 and y= 5
Substuting the values in the equation
ax + y = 20 , we get
3(a) + 5 = 20
3a = 20-5
3a = 15
a = 5
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