If the point (4,3) lies on the linear equation 3x-ky = 6 , find the value of k
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Answer:
K= 2
Step-by-step explanation:
Put the values of x and y i.e X=4 and y= 3
3x- ky = 6
3(4)-k(3) = 6
12-3k = 6
-3k= 6-12
-3k = -6
K = -6/-3
K= 2
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