Math, asked by skis0375, 4 months ago

If the point (5, 6) lies on the graph of the equation 4y + 7 = ax, find the value of ‘a’. do it in rough note plz

Answers

Answered by anushkatyagi703
0

Answer:

because the point (5,6) lies on the graph of 4y+7=ax

hence it must satisfy the equation

4(6)+7=a(5)

24+7=a(5)

31=a(5)

a=\frac{31}{5}

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Answered by Hulkkav
0

Answer:

Step-by-step explanation:

The point which is given (5,6) tells us that the value of x will be 5 and value of y will be 6 as it is of the form (x , y)

So substituting values of x and y in the given equation we get,

4y + 7 = ax

4 (6) + 7 = a(5)

24 + 7 = 5a

31 = 5a

a = 31/5.        

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