Question

if the point (6,9),(10,x)and (-6,-7) are collinear then find the value of x.

Answer 1

Answer:

A(6,9) ,  B(10,X) , C(-6,-7)

WE KNOW THAT , AREA OF COLLINEAR = 0

SO, AREA  = 1/2[X1(y2-y3) + x2(y3-y1) + x3(y1-y2)]

       0 = 1/2 [6(x+7) + 10(-7-9) + (-6)(9-x)]

      0 = 1/2 [6x+42 + 10(-16) + (-54) + 6x ]

     0*2 = [6x+6x+42-160-54]

   0 = [12x + 42 - 214 ]

  0 = [12x - 172 ]

0 =  4(3x - 43)

0/4 = 3x-43

43  = 3x

x = 43/3

Answer 2

Answer:

Step-by-step explanation:

Hope this is helpful.......