Question

if the point (8,-5) lies on the locus x^2÷16- y^2÷25 =k,find the value of k​

Answer 1

Answer:

X^2÷16-y^2÷25=k

Put the values (8,-5)

X=8 ; y= -5

(8)^2÷16-(-5)^2÷25=k

64÷16-25÷25=k

4-1=k

3=k

Answer 2

Answer:

k = 3

Step-by-step explanation:

x^2/16 - y^2/25 = k

as (8,-5) lies on this locus therefore

put x = 8 & y = -5

8^2/16 - (-5)^2/25 = k

64/16 - 25/25 = k

4 - 1 = k

k = 3