If the point (a,a) falls between the lines mod x+y=3, then prove that mod a<1
SARDARshubham:
you are telling lines, but only one line is given
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Answered by
1
if x=a ,y=a
a+a=3
2a=3
a=3-2
a=1
a+a=3
2a=3
a=3-2
a=1
Answered by
1
point (a,a) fall on the line |x+y|=3
therefore
|a+a| = 3
|2a| = 3
a = +3/2 & -3/2
therefore
|a+a| = 3
|2a| = 3
a = +3/2 & -3/2
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