if the point A (x,y),B (3,6).,c(-3,4) are collinear, then show that x-3y+15=0
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SINCE A (X,Y), B (3,6) AND (-3,4) are collinear
Therefore the condition must be satisied by the collinearity .
now
x1( y2-y3)+x2( y3-y1)+x3( y1- y2) = 0
x( 6-4)+3(4-y)-3(y-6) = 0
2x+12-3y-3y+18 = 0
2x-6y+30 = 0
2(x-3y+15 )= 0
x- 3y +15 = 0
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