Question

if the point A6 1 b8 2 c9 4 and DP 3 are the vertices of the parallelogram taken in order find the value of p​

Answer 1

Answer:

Step-by-step explanation:

Let the points be

A(6,1)  B(8,2)  C(9,4) D (p,3)

We know that diagonals of parallelogram bisect each other

So,  is the mid-pint of AC and BD

* We find x co-ordinate of O from both AC and BD

Finding mid-point of AC

We have to find x co-ordinate of O x-coordinate of O$=\frac{x_{1} }{x_{2} }$

Where $xx_{1} =6;x_{2} =9$

Putting values for x-coordinate x-coordinate og O=$\frac{15}{2} (1)$

Finding mid-point of BD

We have to find x co-ordinate of O x-coordinate of O =$\frac{x_{1}+x_{2}  }2{} }$

Where $x_{1} =8;x_{2} =p$

Putting values for x-coordinate x-coordinate of O=$\frac{8+p}{2}$ (2)

Comparing (1) and (2)

$\frac{15}{2} =\frac{8+p}{2} =>15=8+p=>15-8=p=>p=7$

Hence p=7

Answer 2

Answer:

Step-by-step explanation:

p=7