Question

If the point c(-2,3) is equidistant from the points A(3,-1) and B(x, 8), find the values of x. Also, find the distance BC.


sidhe se answer dena nhi ayega mt dena aur goggles mt krna ​

Answer 1

hope it will help u Mister

Answer 2

Answer:

Step-by-step explanation:

Answer

Given: Points C(−2,3) is equidistant from points A(3,−1) and B(x,8).

Then,

CA=CB

or CA2=CB2

CB2=(x+2)2+(8−3)2

CA2=(3+2)2+(−1−3)2

(x+2)2+(8−3)2=(3+2)2+(−1−3)2

(x+2)2+52=52+(−4)2

x2+4x+4+25=25+16

x2+4x+29−41=0

x2+4x−12=0

x2+6x−2x−12=0

x(x+6)−2(x+6)=0

(x+6)(x−2)=0

This implies: x=2 or x=−6

Therefore: AC=$\sqrt{41}$

​ units.

mark me brainliest.