If the point of intersection of ax + by = 7 and bx + ay = 5 is (3, 1) then find the value of a a and b.
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Vedant1Gangurde:
Its R or 2??
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by putting value of x and y (3,1)
3a+b=7...eq1 *3
a+3b=5...eq2 *1
now,
9a+3b=21
a+3b=5
eliminate 3b by sign change
remaining.....8a=16
therefore a=2
3a+b=7...eq1 *3
a+3b=5...eq2 *1
now,
9a+3b=21
a+3b=5
eliminate 3b by sign change
remaining.....8a=16
therefore a=2
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