Question

If the point P(1,4) lies on the line segmentsjoining the point A(3,12) and B(5,20), then find AP/AB​

Answer 1

Answer:

$ap = \sqrt{(x2 - x1) + (y2 - y1)} \\ = \sqrt{ {2}^{2} + {8}^{2} } \\ = \sqrt{68} \\ ab = \sqrt{ {2}^{2} + {8}^{2} } \\ = \sqrt{68} \\ \frac{ap}{ab} = \frac{ \sqrt{68} }{ \sqrt{68} } \\ = \sqrt{ \frac{68}{68} } \\ = \sqrt{1} \\ = 1 \: or \: - 1$

Answer 2

Answer:

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$ap= \sqrt{ ({x}^{2} - {x}^{1} ) + ({y}^{2} - {y}^{1}) } \\</p><p>=>\sqrt{ {2 }^{2} + {8}^{2} } \\</p><p>=> \sqrt{68}$

$ab= \sqrt{ {2}^{2} + {8}^{2} } \\</p><p>=> \sqrt{68}$

$\frac{ap}{ab} = \frac{ \sqrt{68} }{ \sqrt{68} } \\</p><p> = \sqrt{ \frac{68}{68} } \\</p><p> = \sqrt{1}$

Hence,the answer is -1 or 1