Question

If the point p (2,2) is equidistant from the point a(-2,k) and b(-2k,-3), find k. also find the length of ap

Answer 1

Step-by-step explanation:

Mark as brainlest and hope it is corres

Answer 2

Answer:

PA = PB

${pa}^{2} = {pb}^{2} \\ {(2 + 2)}^{2 } + {(2 - k)}^{2} = {(2 + 2k)}^{2} + {(2 + 3)}^{2} \\ {4}^{2} + 4 - 4k + {k}^{2} = 4 + 8k + 4 {k}^{2} + {5}^{2} \\ 16 + 4 - 4k + {k}^{2} = 4 + 8k + {4k}^{2} + 25 \\ {3k}^{2 } + 12k + 9 = 0 \\ {k}^{2} + 4k + 3 = 0 \\ (k + 1)(k + 3) = 0 \\ k = - 1 \: or \: k = - 3 \\ = = = = = = = = = = =$

using the value of k find AP