if the point P has coordinates cos alpha sin alpha find the distance of op where O is the origin
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Answer:
Step-by-step explanation:
Key points to solve the problem:
• Idea of distance formula- Distance between two points P(x1,y1) and Q(x2,y2) is given by- PQ =
Given,
Two points P and Q subtends an angle α at the origin as shown in figure:
From figure we can see that points O,P and Q forms a triangle.
Clearly in ΔOPQ we have:
{from cosine formula in a triangle}
⇒
…..equation 1
From distance formula we have-
OP =
As, coordinates of O are (0, 0) ⇒ x2 = 0 and y2 = 0
Coordinates of P are (x1, y1) ⇒ x1 = x1 and y1 = y1
=
=
Similarly, OQ =
=
And, PQ =
∴ OP2 + OQ2 - PQ2 =
⇒ OP2 + OQ2 - PQ2 =
Using (a-b)2 = a2 + b2 – 2ab
∴ OP2 + OQ2 - PQ2 = 2x1 x2 + 2y1 y2 ….equation 2
From equation 1 and 2 we have:
⇒
…Proved.
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