Question

If the point P (k-1,2)is equidistant from the points A(3,k) and B(k, 5) find the value of K

Answer 1

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Answer 2

"The value of K is 5.

Given:

P is midpoint of the A and B

P is (K-1, 2)

Solution:

We can write  

x = K-1; y = 2

${ x }_{ 1 } = 3; { y }_{ 1 } = K$

${ x }_{ 2 } = K; { y }_{ 2 } = 5$

Mid point formula is$\left( \frac { { x }_{ 1 }+{ x }_{ 2 } }{ 2 } ,\quad \frac { { y }_{ 1 }+{ y }_{ 2 } }{ 2 } \right)$

Substituting values in the formula

$K-1=\frac{3+K}{2}$

2K - 2 = 3 + K

2K - K = 3 + 2

K = 5"