Question

If the points (0,2) is equidistant from points (3,p) and (p,5). Find the value of p​

Answer 1

Answer:

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Answer 2

Answer:

AB = AC

⇒AB =√(3-0)²+(p-2)² and AC =√(p-0)² + (5-2)²

⇒(3-0)² + (p-2)² =(p-0)² + (5-2)²

⇒9 + p² + 4 - 4p = p² + 9

⇒9 - 9 +p² - p² +4 -4p =0

⇒4 - 4p=0

⇒-4p =-4

⇒p = 1

so p=1 is the answer.