If the points (1, 3) , (0, 4) and (k, -2) are collinear, then k =
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Given that,
A(1,3), B(0,4), C(k,-2)
if the points are collinear, then area of the triangle is equal to zero.
area of ∆ABC=1/2|x1(y2-y3)+x2(y3-y1)+x3(y1-y2)|
0=1/2|1(0+2)+0(-2-3)+k(3-4)|
0×2=|1(2)+0+k(-1)|
0=|2-k|
0=2-k
k=2
therefore, the required value of k=2.
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