if the points (10,5), (8,4) and (6,6) are the midpoints of the sides of a triangle. find its vertices.
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continuation,
(2)-(4):
b+d-d-f=10-8
b-f=2.........(8)
(8)+(6):
b-f+b+f=2+12
2b=14
b=7
substitute b=7 in (2)
7+d=10
d=3
substitute d=3 in (4)
3+f=8
f=5
A(8,7) B(12,3) C(4,5)
HOPE IT IS USEFUL TO U
(2)-(4):
b+d-d-f=10-8
b-f=2.........(8)
(8)+(6):
b-f+b+f=2+12
2b=14
b=7
substitute b=7 in (2)
7+d=10
d=3
substitute d=3 in (4)
3+f=8
f=5
A(8,7) B(12,3) C(4,5)
HOPE IT IS USEFUL TO U
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Answered by
62
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