if the points (-2,1),(a, b) and(4,-1)are collinear and a-b= 1, then find value of and b
Answers
Answered by
249
HELLO USER!!
HERE IS YOUR ANSWER in the attachment
value of
a=1
b=0
(a, b) = (1,0)
HOPE IT HELPS YOU
PLZ MARK AS BRAINLIEST IF IT HELPED
^_^
HERE IS YOUR ANSWER in the attachment
value of
a=1
b=0
(a, b) = (1,0)
HOPE IT HELPS YOU
PLZ MARK AS BRAINLIEST IF IT HELPED
^_^
Attachments:
Answered by
92
Answer:
a=1 and b=0
Step-by-step explanation:
given: a-b=1 eq:1
area of triangle=0
1/2[x₁(y₂-y₃)+x₂(y₃-y₁)+x₃(y₁-y₂)=0
-2[(b+1)+a(-1-1)+4(1-b)]=0
-2b-2-2a+4-4b=0
-b-1-a-2b=0 ( dividing by 2)
-a-3b=0
a+3b=0 eq:2
subtracting equation 1 from 2
a+3b-(a-b)=1-1
b=0
and a=1
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