Question

If the points (2k-3, k+2) lies on the graph of the equation 2x+3y+15=0, find values of k.


please answer fast......

Answer 1

Put 2k-3 as x and k+2 as y in the equation.

2(2k-3)+3(k+2)+15=0

4k-6+3k+6+15=0

7k=-15

k=-15/7

Glad to help.

Answer 2

Given Equation is 2x + 3y + 15 = 0.

Given that the points(2k - 3, k + 2) lies on the equation.

Substitute x = 2k - 3 and y = k + 2, we get

⇒ 2(2k - 3) + 3(k + 2) + 15 = 0

⇒ 4k - 6 + 3k + 6 + 15 = 0

⇒ 7k + 15 = 0

⇒ 7k = -15

⇒ k = -15/7.

Therefore, the value of k = -15/7.

Hope it helps!