Question

If the points (3, 4) and (5, x) are on the circular field with centre (4, 2), then find the value of x.

Answer 1

Since A and B lie on the circle having centre 0. Therefore, OA = OB

√(4-2)²+(3-3)² = √((x - 2)² + (5 - 3)²

2= √(x - 2)² +4

(x-2) +4 41

(x - 2)² = 0

X-2=0

x = 2

hope it help