Question

Find the equation of a line parallel to BC and passes through the centroid of ∆ABC where A(-1,4),B(6,2) and C(4,6).​

Answer 1

Answer:

Centroid of AABC whose vertices are

A(2, 2) = (x₁, y₁), B(-4,-4) = (x₂, Y₂) and

C(5, -8)= (X3, Y₁).

Centroid= X₁ + X₂ + X3 Y₁ + y2 + Y3 3 3

=

X₁ X2 X3 V₁ + y2 + Ys

* x2 * x³, V₁ y² y²)3

= (2-4+5,2-4-8)

313 3/10 3' 3

-(1./30)

hope it helps