if the points A (0,2) is equidistant from the point B (3,p), C (p,5) find p also find the length of AB
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given,a=(0,2),b=(3,p),c=(p,5)
given AB=AC
~(3)^2+(2-p)^2=(p)^2+(3)^2
~2-p=p (or) 2-p=-p
~p=1
then AB={(3)^2+1}^1/2=(10)^1/2
given AB=AC
~(3)^2+(2-p)^2=(p)^2+(3)^2
~2-p=p (or) 2-p=-p
~p=1
then AB={(3)^2+1}^1/2=(10)^1/2
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